Pure Mathematics 1

Circular Measure Lesson

Hello. I am going to teach you everything you need to know about circular measure — radians, arc length, sector and segment areas, and small angle approximations. I will assume you know nothing about radians. By the end, you will be solving problems confidently. Let us begin.

1

What is a Radian?

You already know degrees: a full circle is 360°, a right angle is 90°, and so on. But in advanced mathematics, degrees are clumsy. The formulas for arc length, area, and calculus become messy. That is why mathematicians prefer a natural unit: the radian.

Definition of a Radian

One radian is the angle subtended at the centre of a circle when the arc length equals the radius.

Imagine taking the radius of a circle, wrapping it along the circumference — the angle covered by that arc length is exactly 1 radian.

Definition of a Radian 1 radian = angle where arc length = radius

Why Radians?

Degrees were invented by ancient Babylonians (they liked the number 60). Radians are natural — they come from the geometry of the circle itself. When you use radians:

✅ Arc length formula is simply s = rθ (no silly 360/2π factors)

✅ Sector area formula is simply A = ½r²θ

✅ Calculus becomes clean: derivative of sin x is cos x (only works in radians!)

Converting Degrees ↔ Radians

The key relationship: a full circle is 360° which equals 2π radians. Therefore:

Conversion Formulas π rad = 180°

From this one fact, everything follows:

To convert degrees to radians: multiply by π/180

To convert radians to degrees: multiply by 180/π

Teacher's Tip: Memorise this one fact — π rad = 180°. From it you can derive every conversion. π rad = 180° means 1 rad = 180°/π ≈ 57.3°, and 1° = π/180 rad.

Common Angles — Radians and Degrees

Here is a table of the angles you will see most often. Memorise these — they appear in every exam.

DegreesRadians (exact)Radians (approx)
00
30°π/60.5236
45°π/40.7854
60°π/31.0472
90°π/21.5708
120°2π/32.0944
135°3π/42.3562
150°5π/62.6180
180°π3.1416
270°3π/24.7124
360°6.2832

Interactive Converter

Drag the sliders below to convert between degrees and radians in real time.

90.0°
π/2

90° = π/2 rad

Example 1: Convert 60° to radians.

Multiply by π/180: θ = 60 × π/180

θ = 60π/180

Simplify: θ = π/3

Answer: 60° = π/3 rad
Example 2: Convert 5π/6 radians to degrees.

Multiply by 180/π: θ = (5π/6) × 180/π

The π cancels: θ = (5/6) × 180

θ = 5 × 30 = 150

Answer: 5π/6 rad = 150°

Teacher's Tip: When converting, ask yourself: "Am I going from degrees to radians (multiply by π/180) or radians to degrees (multiply by 180/π)?" The π will always end up in the numerator for radians and cancel for degrees. This is your sanity check.

Back to menu
2

Arc Length

An arc is a portion of the circumference of a circle. Finding its length is straightforward once you understand the relationship with the angle.

Derivation

A full circle has circumference 2πr for a full angle of 2π radians. The arc length is proportional to the angle. If the angle is θ radians, then the arc length is the same fraction of the circumference:

Arc Length s = rθ

That is it. The arc length is just the radius multiplied by the angle in radians. Notice: when θ = 2π, we get s = 2πr — the full circumference. When θ = π, we get s = πr — half the circumference. It works perfectly.

Teacher's Tip: The formula s = rθ only works when θ is in radians. If your angle is in degrees, you must convert to radians first. This is the most common mistake students make. Always check: is θ in radians?

Example 3: A circle has radius 5 cm and the angle subtended at the centre is 0.8 radians. Find the arc length.

Formula: s = rθ

s = 5 × 0.8

s = 4

Answer: s = 4 cm
Example 4: A circle has radius 8 cm and the angle subtended is 60°. Find the arc length.

First convert 60° to radians: θ = 60 × π/180 = π/3

Now use s = rθ:

s = 8 × π/3

s = 8π/3 ≈ 8.378

Answer: s = 8π/3 cm ≈ 8.38 cm

Teacher's Tip: Notice in Example 4 the first step was to convert degrees → radians. Always get into the habit of checking the angle unit before using any circular measure formula. Convert first, then apply the formula.

Back to menu
3

Area of a Sector

A sector is the region enclosed by two radii and the arc between them. Think of it as a "pizza slice" of the circle.

Derivation

A full circle has area πr² for a full angle of 2π radians. The area of a sector is proportional to the angle. If the angle is θ radians, the sector area is the same fraction of the full area:

Area of a Sector A = ½ r² θ

Again, notice the pattern: when θ = 2π, A = ½ r² × 2π = πr² — the full circle. When θ = π, A = ½ r²π — half the circle. Perfect.

Example 5: A sector has radius 6 cm and angle 1.2 radians. Find its area.

Formula: A = ½r²θ

A = ½ × 6² × 1.2

A = ½ × 36 × 1.2

A = 18 × 1.2 = 21.6

Answer: A = 21.6 cm²
Example 6: A sector has radius 10 m and angle 45°. Find its area.

Convert 45° to radians: θ = 45 × π/180 = π/4

A = ½r²θ = ½ × 10² × π/4

A = ½ × 100 × π/4

A = 50 × π/4 = 25π/2

Answer: A = 25π/2 m² ≈ 39.27 m²

Teacher's Tip: Notice the similarity: sector area = ½r²θ. Compare this to the area of a triangle = ½ × base × height. If you think of the arc as a curved "base" (length rθ) and the radius as the "height", the formula makes intuitive sense: A ≈ ½ × (rθ) × r = ½r²θ.

Back to menu
4

Area of a Segment

A segment is the region bounded by an arc and the chord connecting its endpoints. It is the sector minus the triangle formed by the two radii and the chord.

Derivation

To find the area of a segment, we simply subtract the area of the triangle from the area of the sector:

Area of a Segment A = ½ r² (θ − sin θ)

Let us break this down:

1. Sector area = ½r²θ

2. Triangle area = ½r² sin θ

Why? The triangle is formed by two sides of length r with included angle θ. Using the formula ½ab sin C gives ½ × r × r × sin θ = ½r² sin θ.

3. Segment area = Sector − Triangle = ½r²θ − ½r² sin θ = ½r²(θ − sin θ)

Example 7: A circle has radius 8 cm and the angle subtended at the centre is 1.2 radians. Find the area of the segment. (sin 1.2 ≈ 0.9320)

Formula: A = ½r²(θ − sin θ)

A = ½ × 64 × (1.2 − 0.9320)

A = 32 × 0.2680

A = 8.576

Answer: A ≈ 8.58 cm²
Example 8: A circle has radius 5 m and the angle is 90°. Find the segment area. (sin(π/2) = 1)

Convert 90° to radians: θ = π/2

A = ½r²(θ − sin θ) = ½ × 25 × (π/2 − 1)

A = 12.5 × (π/2 − 1)

A = 12.5 × (1.5708 − 1)

A ≈ 12.5 × 0.5708 ≈ 7.135

Answer: A ≈ 7.14 m²

Teacher's Tip: The triangle formula ½ab sin C is your friend. Here a = b = r and C = θ, so the triangle area is always ½r² sin θ. Make sure θ is in radians before using it.

Interactive Circle Visualizer

Adjust the angle θ and radius r below to see how the sector, triangle, and segment change. The arc is highlighted in green, the sector in indigo, and the segment (sector − triangle) in red.

Arc: 10.00Sector: 25.00Triangle: Segment:
Back to menu
5

Solving Problems — Compound Shapes

Now that you know all the individual formulas, let us put them together to solve more interesting problems involving compound shapes.

A common type of problem gives you a diagram with a sector, a triangle, and asks for perimeters or areas of shaded regions. The key steps are:

1. Identify all the component shapes (sectors, triangles, straight lines, arcs)

2. Find the necessary measurements (radii, angles in radians)

3. Apply the relevant formulas (s = rθ, A = ½r²θ, A = ½r² sin θ, A = ½r²(θ − sin θ))

4. Add or subtract areas / lengths as needed

Example 9: The diagram shows a sector OAB of a circle with centre O, radius 8 cm, and angle AOB = 1.2 radians. The straight line AB is drawn. Find:
a) the arc length AB
b) the area of sector OAB
c) the area of triangle OAB
d) the area of the segment (shaded region)

a) Arc length AB:

s = rθ = 8 × 1.2 = 9.6 cm

b) Area of sector OAB:

A_sector = ½r²θ = ½ × 64 × 1.2 = 32 × 1.2 = 38.4 cm²

c) Area of triangle OAB:

A_tri = ½r² sin θ = ½ × 64 × sin(1.2)

sin(1.2) ≈ 0.9320

A_tri = 32 × 0.9320 ≈ 29.82 cm²

d) Area of segment:

A_seg = A_sector − A_tri = 38.4 − 29.82 ≈ 8.58 cm²

a) 9.6 cm  |  b) 38.4 cm²  |  c) 29.82 cm²  |  d) 8.58 cm²
Example 10: A shape consists of a sector OAB (radius 6 cm, angle 60°) joined to a right triangle A C D along side OA. The total perimeter of the shape includes the arc, two straight radii, and side AC. Find the total perimeter and total area.

First convert 60° to radians: θ = π/3

Arc length AB: s = rθ = 6 × π/3 = 2π ≈ 6.283 cm

The two radii each are length r = 6 cm.

Perimeter = arc + 2 radii = 2π + 12 ≈ 18.283 cm

Sector area: A = ½r²θ = ½ × 36 × π/3 = 6π ≈ 18.85 cm²

Perimeter ≈ 18.28 cm  |  Area ≈ 18.85 cm²

Teacher's Tip: When solving compound shape problems, draw the shape, label everything you know, then work step by step. Always check: are my angles in radians? If not, convert them first. Break the problem into smaller parts and solve each one separately.

Back to menu
6

Small Angle Approximations

When the angle θ is very small (in radians), something remarkable happens: the trigonometric functions simplify to algebraic expressions. This is incredibly useful in physics, engineering, and calculus.

The Approximations

For small θ (in radians):

Small Angle Approximations (θ in radians, small) sin θ ≈ θ     tan θ ≈ θ     cos θ ≈ 1 − θ²/2

Why This Works

Imagine a very small angle drawn at the centre of a unit circle. The arc length is θ, the vertical side (sin θ) is almost the same length as the arc, and the horizontal side (cos θ) is almost 1. As θ gets smaller, sin θ and tan θ get closer and closer to θ itself.

These approximations come from the Taylor series expansions of sin, cos, and tan around θ = 0:

sin θ = θ − θ³/6 + θ⁵/120 − ...

cos θ = 1 − θ²/2 + θ⁴/24 − ...

tan θ = θ + θ³/3 + 2θ⁵/15 + ...

For small θ, the higher powers become negligible, leaving only the first term.

Teacher's Tip: These approximations only work when θ is in radians and is small (typically |θ| < 0.1 rad for error < 1%). The smaller θ is, the more accurate the approximation. For θ = 0.1 rad, sin 0.1 ≈ 0.0998 — the error is only about 0.2%.

Example 11: Approximate sin(0.12) using a small angle approximation.

Since 0.12 is small, use sin θ ≈ θ

sin(0.12) ≈ 0.12

(For reference: calculator gives sin(0.12) ≈ 0.1197 — the error is only 0.0003!)

Answer: sin(0.12) ≈ 0.12
Example 12: Approximate tan(0.08) + cos(0.08) using small angle approximations.

tan(0.08) ≈ 0.08

cos(0.08) ≈ 1 − (0.08)²/2 = 1 − 0.0032 = 0.9968

tan(0.08) + cos(0.08) ≈ 0.08 + 0.9968 = 1.0768

Answer: ≈ 1.0768

Teacher's Tip: The cos approximation is different from sin and tan — it starts with 1, not 0. This makes sense: when θ = 0, cos 0 = 1. The correction term −θ²/2 is negative because cos θ decreases from 1 as θ increases from 0.

Back to menu
7

Practice — Step by Step

Solve each problem one step at a time. Type your answer for each step and click Check Step. You must get each step correct before moving to the next.

Back to menu
8

Mastery Kit

"
Geometry is the art of correct reasoning from incorrect diagrams.
— Henri Poincaré
Quick Hacks
  • π = 180°: Memorise this one fact and you can derive any conversion. π rad = 180° is the single most important equation in circular measure.
  • Common radian values: 30° = π/6, 45° = π/4, 60° = π/3, 90° = π/2, 180° = π. Learn these cold.
  • Arc length shortcut: s = rθ — think "radius times angle." No extra constants to memorise.
  • Sector area trick: A = ½r²θ looks like ½ × base × height if you imagine the arc (rθ) as the base and r as the height.
  • Small angle sanity: For θ < 0.1 rad, sin θ ≈ θ gives error < 0.2%. Good enough for most approximations.
  • Segment = sector − triangle: Never memorise the segment formula separately — just remember A_seg = A_sector − A_triangle = ½r²θ − ½r² sin θ.
📌 Key Notes
  • Radians first: Every formula in this lesson assumes θ is in radians. Convert degrees to radians before applying any formula.
  • Conversion factor: Multiply by π/180 for degrees→radians, by 180/π for radians→degrees. The π always goes with the radians.
  • Arc length s = rθ: When θ = 2π, s = 2πr (full circumference). This is a good sanity check.
  • Sector area A = ½r²θ: When θ = 2π, A = πr² (full circle). Checks out.
  • Segment area: The triangle area ½r² sin θ comes from the formula ½ab sin C with a = b = r and C = θ.
  • Small angles only: sin θ ≈ θ is only valid for small θ in radians. Never use it for θ > 0.5 rad.
⚠️ Common Mistakes
  • Using degrees in formulas: The most common error. s = rθ and A = ½r²θ give completely wrong answers if θ is in degrees. Always convert to radians first.
  • Wrong conversion direction: Degrees → radians: multiply by π/180. Radians → degrees: multiply by 180/π. Mixing these up gives nonsense.
  • Forgetting the ½ in sector area: A = ½r²θ, not r²θ. The ½ is essential. Compare with triangle area: ½ × base × height.
  • Segment area: forgetting to subtract: The segment is sector minus triangle, not the other way around. If you get a negative area, you subtracted in the wrong order.
  • Small angle overuse: sin θ ≈ θ is NOT accurate for large angles. For θ = 30° (0.524 rad), sin 30° = 0.5 but θ = 0.524 — the error is 4.8%. Only use it for small θ.
🧠 Cheat Sheet — All Formulas
π rad = 180°
Deg → Rad: × π/180
Rad → Deg: × 180/π
Arc length: s = rθ
Sector area: A = ½r²θ
Segment area: A = ½r²(θ − sin θ)
Triangle area: A = ½r² sin θ
sin θ ≈ θ   tan θ ≈ θ   cos θ ≈ 1 − θ²/2
💡

The Golden Rule of Circular Measure

Always check your angle unit before applying any formula. If the angle is in degrees, convert it to radians first. Every. Single. Time. This one habit will save you more marks than anything else.

Back to menu

You Have Completed the Circular Measure Lesson

Here is what you have learned:

  • ✅ What a radian is and why it is better than degrees
  • ✅ Converting between degrees and radians (π rad = 180°)
  • ✅ Arc length formula: s = rθ
  • ✅ Sector area formula: A = ½r²θ
  • ✅ Segment area formula: A = ½r²(θ − sin θ)
  • ✅ Solving compound shape problems combining arcs, sectors, and triangles
  • ✅ Small angle approximations: sin θ ≈ θ, tan θ ≈ θ, cos θ ≈ 1 − θ²/2

Well done. You now understand circular measure. This is essential for A-level Pure Maths — radians appear in trigonometry, calculus, and everything that follows.